Question

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages are labeled as 8 ounces, the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces. A sample of 50 packages is selected periodically, and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces. Suppose that in a particular sample of 50 packages, the mean amount dispensed is 8.152 ounces, with a sample standard deviation of 0.046 ounce.

question 1

Is there evidence that the population mean amount is different from 8.17 ounces( use a 0.10 level of significance)

state the null and alternate hypothesis?

Identify the critical values?

determine the test statistic and state the conclusion?

question 2

determine the p value (round to 4 decimals places) and interpret the meaning?

Choose the correct answer below. A. The p-value is the probability of not rejecting the null hypothesis when it is false. B. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.015 ounce below 8.17 if the null hypothesis is false. C. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.015 ounce above 8.17 if the null hypothesis is false. D. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.015 ounce away from 8.17 if the null hypothesis is true.

Answer #1

Step 1

Ho: = 8.17

Ha: 8.17

Step 2: Test statistics

n = 50

sample mean = 8.152

sample sd = 0.046

Assuming that the data is normally distributed and also as the population sd is not given, we will use t stat

t = - 2.767

Step 3

df = 49

= 0.10

t critical (two tailed test) = +/- 1.67655090

p value = 0.0080

As the t stat falls in the rejction area, we reject the Null hypothesis.

Also as the p value is less than , we reject the Null hypothesis.

D. The p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.015 ounce away from 8.17 if the null hypothesis is true.

A manufacturer of chocolate candies uses machines to package
candies as they move along a filling line. Although the packages
are labeled as eight ounces, the company wants the packages to
contain a mean of 8.17 ounces so that virtually none of the
packages contain less than eight ounces. A sample of 50 packages is
selected periodically, and the packaging process is stopped if
there is evidence that the mean amount packaged is different from
8.17 ounces. Suppose that in...

A manufacturer of chocolate candies uses machines to package
candies as they move along a filling line. Although the packages
are labeled as 8 ounces, the company wants the packages to contain
a mean of 8.17 ounces so that virtually none of the packages
contain less than 8 ounces. A sample of 50 packages is selected
periodically, and the packaging process is stopped if there is
evidence that the mean amount packaged is different from 8.17
ounces. Suppose that in...

A manufacturer of chocolate candies uses machines to package
candies as they move along a filling line. Although the
packages are labeled as 8 ounces, the company wants the packages to
contain a mean of 8.17 ounces so that the probability of producing
a package that contains less than 8 ounces is very
small. A sample of 50 packages is selected periodically
and weighed, and the packaging process is stopped if there is
evidence that the mean packaged amount is statistically different...

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"Hot Tamales" are chewy, cinnamon flavored candies. A bulk
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deviation of 0.7.
A.) To test whether the true mean of candies dispensed is
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"Hot Tamales" are chewey, cinnamon flavored candies. A bulk
vending machine is known to dispense, on average, 15 Hot Tamales
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A) to test whether the true mean of candies dispensed is
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The average weight of a package of rolled oats is supposed to be
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