Question

17. The average cost of providing a particular service per person per day is a random...

17. The average cost of providing a particular service per person per day is a random variable having a normal distribution with average of N$100 and a standard deviation of N$22. This is an illustration a

Select one:

A. Discrete Probability Distribution

B. Continuous Probability Distribution

18.

If you use the information provided in Question 3.1 to calculate the probability that the cost of providing the service will be at least N$120 per day per person., then :-

Select one:

A. P ( x is greater and equal to 120 )

B. P ( x is smaller and equal to 120)

19.

Based upon the information provided above in this Question, the z-distribution will be as follows:

Select one:

A. P( Z in greater and equal to 0.91 )

B. P ( z is smaller and equal to 0.91)

C. P ( z is smaller and equal to - 0.91)

D. P ( z is greater and equal to - 0.91 )

20.

Based upon the above information obtained in this Question, which one of the following statements below is correct:

Select one:

a. Probability for the cost of the service to be at least N$120 = 31.86%

b. Probability for the cost of the service to be at least       N$120 = 81.86%

c. Probability for the cost of the service to be at least       N$120 = 18.14%

d. None of the provided

21.

The average cost of providing a particular service per person per day is a random variable having a normal distribution with average of N$100 and a standard deviation of N$22. Thus, calculate the probability that the cost of providing the service will be at most N$60 per day per person.

Select one:

A. P ( X is greater and equal to 60 )

B. P ( X is smaller and equal to 60 )

C. None of the provided

22.

The average cost of providing a particular service per person per day is a random variable having a normal distribution with average of N$100 and a standard deviation of N$22. Thus, calculate the probability that the cost of providing the service will be at most N$60 per day per person.

Select one:

A. P ( X is greater and equal to 60 )

B. P ( X is smaller and equal to 60 )

C. None of the provided

23

Based upon the above information obtained above in this Question, which one of the following statements below is correct :

Select one:

A. Probability for the cost of the service to be at most N$ 60 = 46.56%

B. Probability for the cost of the service to be at most N$ 60 = 96.56%

C. Probability for the cost of the service to be at most N$ 60 = 3.34 %

D. None of the provided

Homework Answers

Answer #1

Solution :

17)

Option B

Continuous Probability Distribution

18)

Option A

P ( x is greater and equal to 120 )

19)

Option A

P( Z in greater and equal to 0.91 )

20)

Option C

Probability for the cost of the service to be at least       N$120 = 18.14%

21)

Option B

P ( X is smaller and equal to 60 )

22)

Option B

P ( X is smaller and equal to 60 )

23)

Option C Probability for the cost of the service to be at most N$ 60 = 3.34 %

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Researchers found that a person in a particular country spent an average of 4.6 hours a...
Researchers found that a person in a particular country spent an average of 4.6 hours a day watching TV in 2010. Assume the population standard deviation is 1.6 hours per day. A sample of 40 people averaged 4.9 hours of television viewing per day. Does this result support the findings of the​ study? z Subscript x overbar equalsnothing ​(Round to two decimal places as​ needed.) Upper P left parenthesis x overbar greater than 4.9 right parenthesis equalsnothing ​(Round to four...
The average amount of money spent for lunch per person in the college cafeteria is $6.93...
The average amount of money spent for lunch per person in the college cafeteria is $6.93 and the standard deviation is $2.61. Suppose that 17 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal placeswhere possible. What is the distribution of X?X ~ N(,) What is the distribution of x¯? x¯ ~ N(,) For a single randomly selected lunch patron, find the probability that this patron's lunch cost...
1a) Assume the annual day care cost per child is normally distributed with a mean of...
1a) Assume the annual day care cost per child is normally distributed with a mean of $8000 and a standard deviation of $500. In a random sample of 120 families, how many of the families would we expect to pay more than $7295 annually for day care per child? P(x > 7295) = ____% The number of families that we expect pay more than $7295 is _____ 1b) A machine used to fill gallon-sized paint cans is regulated so that...
Suppose a study reported that the average person watched 3.95 hours of television per day. A...
Suppose a study reported that the average person watched 3.95 hours of television per day. A random sample of 15 people gave the number of hours of television watched per day shown. At the 11​% significance​ level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from the value reported in the​ study? (Note: x overbarxequals=4.587 hours and sequals=1.038 ​hours.) what Is the p value?
The average time for a particular LED TV needs first service is 415 days with standard...
The average time for a particular LED TV needs first service is 415 days with standard deviation of 30 days. The manufacturer gives one year (365 days) onsite service warranty for newly bought TVs. Assume that the times for first service call are approximately normally distributed. Let X denote the time until the first service for an LED TV. a. The distribution of X is (i) Standard normal with mean 0 and variance 1. (ii) Normal with mean 415 days...
Q: If you receive on average 2 spam emails per day, what is the probability that...
Q: If you receive on average 2 spam emails per day, what is the probability that you don't receive any spam email on a given day? Q: Given P(X)=0.2 P(X)=0.2, P(Y)=0.3 P(Y)=0.3 and P(X∩Y)=0.1 P(X∩Y)=0.1, what is P(X|Y)P(X|Y)? Q: What is the smallest possible sample mean of a bootstrap sample that you can obtain from the sample [1,2,3,4,5]? Q: An insurance company records on average 10 CTP claims per day. What is the probability that on a particular day at...
The percent of fat calories that a person in America consumes each day is normally distributed...
The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about   45   and a standard deviation of   7.5 . Suppose that one individual is randomly chosen. Let   X=   percent of fat calories. In each appropriate box you are to enter either a rational number in "p/q" format or a decimal value accurate to the nearest   0.01 . (.25)   X∼    (pick one) UBNE   (    ,    ) . (.25) The probability that a person consumes...
2. The random variable X denotes the average cost of out-of-state tuition with a mean of...
2. The random variable X denotes the average cost of out-of-state tuition with a mean of $25,600 and a variance of 1,000,000, i.e .X ∼ N ( 25 , 600 ; 1 , 000 , 000 ).    If a random student is chosen in the US what is the probability their out of state tuition is greater than $24,100? 2B) What is the probability that a random out of state student has out-of-state tuition greater than 25,000 and less...
Among a random sample of 37 smokers, the average number of cigarettes smoked per day per...
Among a random sample of 37 smokers, the average number of cigarettes smoked per day per person is 22.0 with a standard deviation of 10.8. Perform a test of significance to determine if it is likely that on average smokers will smoke more than 17 cigarettes a day. a) H_0: mu (=, >, <, or not equal to)  17 H_a: mu (=, >, <, or not equal to)  17 b) Is the CLT for means valid? (yes/no) c) Calculate the test statistic  (use...
The average amount of money spent for lunch per person in the college cafeteria is $7.42...
The average amount of money spent for lunch per person in the college cafeteria is $7.42 and the standard deviation is $2.71. Suppose that 16 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible. What is the distribution of XX? XX ~ N( , ) What is the distribution of ¯xx¯? ¯xx¯ ~ N( , ) For a single randomly selected lunch patron, find the...