Beth is taking a 7-question multiple-choice test for which each question has three answer choices, only one of which is correct. Beth decides on answers by rolling a fair die and marking the first answer choice if the die shows 1 or 2, the second if it shows 3 or 4, and the third if it shows 5 or 6. Find the probability that she gets exactly 5 correct answers.
Given:- n=7 ,where n is multiple choice questions
Beth roll dice and answer the MCQ,.
if beth roll (1 or 2 ) :- mark 1st answer choice
If beth roll (3 or 4) :- mark 2nd answer choice
If beth roll (5 or 6) :- mark 3rd answer choice
Solution:-
x = number of correct answer
n =7
Probability of choosing correct answer (p)=2/6 =1/3
Here trials are independent from each other and probability of choosing correct answer is constant for each trials. That's why we use binomial distribution.
therefore, q=1-p =2/3
Probability that she get exactly 5 correct answer:-
P(x=5) =
=0.0369
Hence, the probability that she get exactly 5 correct answer is 0.0369
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