The population parameters below describe the full-time equivalent number of students (FTES) each year at Lake Tahoe Community College from 1976–1977 through 2004–2005. μ = 1000 FTES median = 1,014 FTES σ = 474 FTES first quartile = 528.5 FTES third quartile = 1,447.5 FTES n = 29 years
a. 75% of all years have an FTES at or below__ .
b. 75% of all years have an FTES at or above __ .
c. The population standard deviation is __ FTES.
d. What percent of the FTES were from 528.5 to 1447.5? __%
f. How many standard deviations away from the mean is the median? Round to two decimal places.
I know you only are required to answer one, but if you know how to do the rest I could really use your help.
Sol)
Given
Mean = 1000
S.D = 474
Median = 1014
Q1 = 528.5
Q3 = 1447.5
N = 29
a)
75% of all years have an FTES at or below
The answer is third quartile
Q3 = 1447.5
b)
75% of all years have an FTES at or above
The answer is first quartile
Q1 = 528.5
c)
Population standard deviation is
S.D = 474
d)
What percent of FTES are from 528.5 to 1447.5
528.5 is the first quartile = 25%
1447.5 is the thirsmd quartile = 75%
= 75 - 25
= 50%
50% of FTES were from 528.5 to 1447.5
f)
How many S.D's away from mean is median
Mean = 1000
Median = 1014
Mod = | mean - median |
= | 1000 - 1014 |
= | -14 |
= 14
x = 14 / 474 = 0.029
The median is 0.029 standard deviations away from the mean
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