Question

A random sample of 40 adults with no children under the age of 18 years results...

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.62 ​hours, with a standard deviation of 2.45 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.41 ​hours, with a standard deviation of 1.64 hours. Construct and interpret a 90​% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesis. Let mu 1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2 represent the mean leisure hours of adults with children under the age of 18. The 90​% confidence interval for left parenthesis mu 1 minus mu 2 right parenthesis is the range from nothing hours to nothing hours. ​(Round to two decimal places as​ needed.)

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 4040 adults with no children under the age of 18 years results...
A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.345.34 ​hours, with a standard deviation of 2.372.37 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.124.12 ​hours, with a standard deviation of 1.641.64 hours. Construct and interpret a 9090​% confidence interval for the mean difference in leisure time between adults with no...
A random sample of 40 adults with no children under the age of 18 years results...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.96 ​hours, with a standard deviation of 2.35 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.32 ​hours, with a standard deviation of 1.52 hours. Construct and interpret a 95​% confidence interval for the mean difference in leisure time between adults with no...
A random sample of 40 adults with no children under the age of 18 years results...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.04 hours, with a standard deviation of 2.26 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.28 ​hours, with a standard deviation of 1.73 hours. Construct and interpret a 90​% confidence interval for the mean difference in leisure time between adults with no...
In December 2001, 38% of adults with children under the age of 18 reported that their...
In December 2001, 38% of adults with children under the age of 18 reported that their family at dinner together seven nights a week. In recent poll, 403 of 1122 adults with children under the age of 18 reported that their family at dinner together seven nights a week. the researcher wishes to estimate the current proportion of families with children under the age of 18 who eat dinner together seven nights a week with 95% confidence. a. what type...
The table to the right shows the results of a survey in which 2558 adults from...
The table to the right shows the results of a survey in which 2558 adults from Country? A, 1104 adults from Country? B, and 1060 adults from Country C were asked if human activity contributes to global warming. Complete parts? (a), (b), and? (c). Adults who say that human activity contributes to global warming Country Upper A 60 ?% Country Upper B 87 ?% Country Upper C 93 ?% ?(a) Construct a 90 ?% confidence interval for the proportion of...
In a random sample of 21 ​people, the mean commute time to work was 31.3 minutes...
In a random sample of 21 ​people, the mean commute time to work was 31.3 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 98​% confidence interval for the population mean mu. What is the margin of error of mu​? Interpret the results. The confidence interval for the population mean mu is left parenthesis nothing comma nothing right parenthesis . ​(Round to one decimal place as​ needed.) The...
In a previous​ poll, 34​% of adults with children under the age of 18 reported that...
In a previous​ poll, 34​% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose​ that, in a more recent​ poll, 372 of 1146 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has​ decreased?...
A random sample of the closing stock prices in dollars for a company in a recent...
A random sample of the closing stock prices in dollars for a company in a recent year is listed below. Assume that sigma is ​$2.29. Construct the 90​% and 99​% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. 18.16 17.37 20.79 21.54 16.89 19.22 22.91 18.71 15.42 15.21 20.67 20.85 18.53 22.85 18.47 17.13 The​ 90% confidence interval is left parenthesis $ nothing comma $ nothing right parenthesis . ​(Round to...
In a previous​ poll, 35​% of adults with children under the age of 18 reported that...
In a previous​ poll, 35​% of adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Suppose​ that, in a more recent​ poll, 445 of 1300 adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together 7 nights a week has decreased...
In a previous​ poll, 41​% of adults with children under the age of 18 reported that...
In a previous​ poll, 41​% of adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Suppose​ that, in a more recent​ poll, 401 of 1050 adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together 7 nights a week has decreased...