Construct both a 9999% and a 8080% confidence interval for
?1
?̂1=48, ?=2.4, ????=48, ?=19
Construct both a 9999% and a 8080% confidence interval for
?1
?̂1=48, ?=2.4, ????=48, ?=19
24,19,21,20,18,19,16,17,21,20,18,16,21,17,19,17,17,16,16,19,15,23
a. Construct a
9999%
confidence interval estimate for the population mean miles per
gallon of...
24,19,21,20,18,19,16,17,21,20,18,16,21,17,19,17,17,16,16,19,15,23
a. Construct a
9999%
confidence interval estimate for the population mean miles per
gallon of 2008 SUVs priced under $30,000, assuming a normal
distribution.
nothing less than or equals≤muμless than or equals≤nothing
(Round to two decimal places as needed.)
Construct both a 9090% and a 9595% confidence interval for
β1β1.
β^1=38, s=6.4, SSxx=45, n=10β^1=38, s=6.4,...
Construct both a 9090% and a 9595% confidence interval for
β1β1.
β^1=38, s=6.4, SSxx=45, n=10β^1=38, s=6.4, SSxx=45, n=10
90% : ≤β1≤≤β1≤
95% : ≤β1≤≤β1≤
Note: You can earn partial credit on this
problem.
II. Please construct the confidence interval for the
following example. First, compute the confidence interval. Second,...
II. Please construct the confidence interval for the
following example. First, compute the confidence interval. Second,
point out the margin of error. Third, point out the width of the
confidence interval. Finally, , interpret the final result in the
context. (Formula and computation)
A random sample of 178 households
reported an average of 2.1 TV sets per household. The sample
standard deviation is 0.1. What would be the confidence interval?
Please construct the confidence interval at the 99% confidence
level,...