Question

3.) List the probability value for each possibility in the binomial experiment calculated at the beginning of this lab, which was calculated with the probability of success being 1/2. (Complete sentence not necessary; round your answers three decimal places).

P(x=0)	0.001		P(x=6)	0.205
P(x=1)	0.010		P(x=7)	0.117
P(x=2)	0.044		P(x=8)	0.044
P(x=3)	0.117		P(x=9)	0.010
P(x=4)	0.205		P(x=10)	0.001
P(x=5)	0.246

4.) Give the probability for the following based on the calculations in question 3 above, with the probability of a success being ½. (Complete sentence not necessary; round your answers to three decimal places)

P(x≥2)			P(x<0)
P(x>2)			P(x≤5)
P(5<x ≤7)			P(x<5 or x≥7)

Answer 1

Solution(4)
binomial probability for each event is given in the question
Solution(4a)
So we need to calculate
P(X>=2) on the basis of Question 3 answer
P(X>=2) = 1 - P(X<2) = 1 - P(X=0) - P(X=1) = 1- 0.001 - 0.010 = 0.989
Solution(4b)
P(X>2) = 1 - P(X<=2) = 1 - P(X=0) - P(X=1) - P(X=2) = 1 - 0.001 - 0.010 - 0.044 = 0.945
Solution(4c)
P(5<X<=7) = P(X=6) + P(X=7) = 0.246 + 0.205 = 0.451
Solution(4d)
P(X<0) = 0
Solution(4e)
P(X<=5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) = 0.001 + 0.010 + 0.044 + 0.117 + 0.205 + 0.246 = 0.623
Solution(4f)
P(X<5 or X>=7) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=7) + P(X=8) + P(X=9) + P(X=10) = 0.001 + 0.010 + 0.044 + 0.117 + 0.205 + 0.117 + 0.044 + 0.010 + 0.001 = 0.549