Question

1. Prospective voters in four cities were questioned regarding their party preferences. 100 individuals were surveyed in each city to determine if there is a significant difference among the cities regarding party preference. The results were:

   Party            City 1         City 2         City3         City 4         Total

   Party A        46                 73               57              62            238

   Party B        54                 27               43              38            162

   Total            100               100            100            100            400

   True or False: The correct null and alternate hypothesis statements for this problem are:

   H₀: There is a difference in party preference.

   H₁: There is no difference in party preference.

   True

   False

QUESTION 9

1. Calculate the Theoretical (Expected) Frequency for the “Party A” choice in the previous problem.   

QUESTION 10

1. What is the table (critical) value of Chi-Square for use in a Decision Rule in the four cities problem? Use an alpha of .05

Answer 1

False

The correct null and alternate hypothesis statements for this problem are:

H₀: There is no difference in party preference.

H₁: There is a difference in party preference.

9.

Theoretical (Expected) Frequency for the “Party A” and City 1 = (Total for Party A) * (Total for City 1) / Grand Total

= (238 * 100) / 400 = 59.5

Theoretical (Expected) Frequency for the “Party A” and City 2 = (Total for Party A) * (Total for City 2) / Grand Total

= (238 * 100) / 400 = 59.5

Theoretical (Expected) Frequency for the “Party A” and City 3 = (Total for Party A) * (Total for City 3) / Grand Total

= (238 * 100) / 400 = 59.5

Theoretical (Expected) Frequency for the “Party A” and City 4 = (Total for Party A) * (Total for City 4) / Grand Total

= (238 * 100) / 400 = 59.5

10.

Degree of freedom = (row - 1) * (col - 1) = (2 - 1) * (4 - 1) = 3

Critical value of Chi-Square at alpha of .05 and df = 3 is 7.81