For independent X and Y, we have probability density function for them where pdf of X is f(x) = ne^-nx and pdf of Y is f(y) = me^-my. (x and y greater than 0). Let M1=max(X,Y) and M2=min(X,Y). Find cov(M2,M1).
the proof is given without using the joint distribution of min anf max. For any query in above comment
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