Question

A city wants to know if a new advertising campaign to make citizens aware of the...

A city wants to know if a new advertising campaign to make citizens aware of the dangers of driving after drinking has been effective. The accompanying table shows the number of drivers who have been stopped with more alcohol in their systems than the law allows for each day of the week in the week before and the week a month after the campaign starts. Assume that the data from each population is Normally distributed. Complete parts a through i below.

Day of the Week Before After
M 10 1
T 11 5
W 3 4
Th 10 4
F 8 8
S 13 7
Su 6 6

) Are the data​ paired? Explain.

Choose the correct answer below.

A.

​No, they are not paired because the drivers are independent of each other.

B.​Yes, because the before counts were compared to the counts after the

advertisement.

C.​Yes, because each day of the week was compared before and after the

advertisement.

​b) Compute the mean difference.

Find the mean difference of

​(beforeminus−​after).

d overbardequals=nothing

drivers

​(Round to three decimal places as​ needed.)

​c) Compute the standard deviation of the differences.

s Subscript dsdequals=nothing

​(Round to three decimal places as​ needed.)

​d) Compute the standard error of the mean difference.

SE left parenthesis d overbar right parenthesisSEdequals=nothing

​(Round to three decimal places as​ needed.)

​e) Find the value of the​ t-statistic.

tequals=nothing

​(Round to three decimal places as​ needed.)

​f) How many degrees of freedom does the​ t-statistic have?

dfequals=nothing

​g) Is the alternative​ one- or​ two-sided? Explain.

Choose the correct answer below.

A.

It is​ two-sided, because the city wants want to know if the advertisement changed the number of drunk drivers.

B.

It is​ two-sided, because the city wants to know if the advertisement lowers the number of drunk drivers.

C.

It is​ one-sided, because the city wants to know if the advertisement changed the number of drunk drivers.

D.

It is​ one-sided, because the city wants to know if the advertisement lowers the number of drunk drivers.

​h) What is the​ P-value associated with this​ t-statistic? Assume that the other assumptions and conditions for inference are met.

​P-valueequals=nothing

​(Round to three decimal places as​ needed.)

​i) At

alphaαequals=0.100.10​,

what do you​ conclude?

Reject

Fail to reject

Upper H 0H0.

There

is not

is

sufficient evidence to conclude that the advertising lowered the mean number of drunk drivers on the road

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A city wants to know if a new advertising campaign to make citizens aware of the...
A city wants to know if a new advertising campaign to make citizens aware of the dangers of driving after drinking has been effective. They count the number of drivers who have been stopped with more alcohol in their systems than the law allows for each day of the week in the week before and the week a month after the campaign starts. Let Di be the difference between the number of drivers caught with excessive alcohol in their systems...
Use this information to answer the following 6 questions:: A city wants to know if a...
Use this information to answer the following 6 questions:: A city wants to know if a new advertising campaign, to make citizens aware of the dangers of drunk driving, has been effective. They count the number of drivers who have been stopped with more alcohol in their systems than the law allows for each day of the week in the week before and the week a month after the campaign starts. The results are in this table: Day of Week...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 44 who smoke. Suppose a sample of 2653 Americans over 44 is drawn. Of these people, 2149 don't smoke. A. Using the data, estimate the proportion of Americans over 44 who smoke. Enter your answer as a fraction or a decimal number rounded to three decimal places. B. Using the data, construct the 99% confidence interval for the population proportion...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 46 who smoke. Suppose a sample of 2022 Americans over 46 is drawn. Of these people, 521 smoke. Using the data, construct the 90% confidence interval for the population proportion of Americans over 46 who smoke. Round your answers to three decimal places. x= n= p ̂= Z= T he confidence interval for the population proportion is Lower limit: Upper...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 4040 who smoke. Step 1 of 2: Suppose a sample of 2172 Americans over 40 is drawn. Of these people, 390 smoke. Using the data, estimate the proportion of Americans over 40 who smoke. Enter your answer as a fraction or a decimal number rounded to three decimal places. Step 2 of 2: Suppose a sample of 2172 Americans over...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 38 who smoke. Step 1: Suppose a sample of 273 Americans over 38 is drawn. Of these people, 79 smoke. Using the data, estimate the proportion of Americans over 38 who smoke. Enter your answer as a fraction or a decimal number rounded to three decimal places. Step 2: Suppose a sample of 273 Americans over 38 is drawn. Of...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 20 who smoke. Step 2 of 2 : Suppose a sample of 966 Americans over 20 is drawn. Of these people, 783 don't smoke. Using the data, construct the 98% confidence interval for the population proportion of Americans over 20 who smoke. Round your answers to three decimal places.
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 33 who smoke. Step 2 of 2: Suppose a sample of 1179 Americans over 33 is drawn. Of these people, 271 smoke. Using the data, construct the 99% confidence interval for the population proportion of Americans over 33 who smoke. Round your answers to three decimal places.
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 50 who smoke. Step 2 of 2 : Suppose a sample of 2851 Americans over 50 is drawn. Of these people, 1911 don't smoke. Using the data, construct the 98% confidence interval for the population proportion of Americans over 50 who smoke. Round your answers to three decimal places.
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the...
The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 40 who smoke. Step 2 of 2: Suppose a sample of 2172 Americans over 40 is drawn. Of these people, 1782 don't smoke. Using the data, construct the 98% confidence interval for the population proportion of Americans over 40 who smoke. Round your answers to three decimal places.