How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution. 45 100 115 55 85 120 30 23 100 110 105 95 105 60 110 120 95 90 60 70 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.) x = $ s = $ (b) Using the given data as representative of the population of prices of all summer sleeping bags, find a 90% confidence interval for the mean price μ of all summer sleeping bags. (Round your answers to two decimal places.) lower limit $ upper limit $
a)
mean = x = 84.65
standard deviation = s = 29.84
b)
sample mean 'x̄= | 84.65 | |
sample size n= | 20 | |
sample std deviation s= | 29.839 | |
std error 'sx=s/√n= | 6.6721 | |
for 90% CI; and 19 df, value of t= | 1.729132812 | |
margin of error E=t*std error = | 11.53697089 | |
lower bound=sample mean-E = | 73.11302911 | |
Upper bound=sample mean+E = | 96.18697089 | |
from above 90% confidence interval for population mean =(73.1130,96.1869) |
Lower limit = 73.11
Upper limit = 96.19
Get Answers For Free
Most questions answered within 1 hours.