The height of men is a normally distrubuted variable with a mean
of 67 inches and a standard deviation of 2.8 inches.
**Round answers to ONE decimal place**
a.) What is the minimum height you could be to be
considered in the top 15% of tallest men?
b.) What is the tallest you could be to be
considered in the shortest 20% of men?
Solution:-
Given that,
mean = = 67
standard deviation = = 2.8
Using standard normal table,
P(Z > z) = 15%
= 1 - P(Z < z) = 0.15
= P(Z < z) = 1 - 0.15
= P(Z < z ) = 0.85
= P(Z <1.04 ) = 0.85
z = 1.04 ( using z table )
Using z-score formula,
x = z * +
x = 1.04 * 2.8+67
x = 69.9
(B)
Using standard normal table,
P(Z < z) = 20%
= P(Z < z) = 0.20
= P(Z < -0.84) = 0.20
z = -0.84 Using standard normal z table,
Using z-score formula
x= z * +
x=-0.84 *2.8+67
x= 64.648
x=64.6
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