Let x be a random variable representing percentage change in neighborhood population in the past few years, and let y be a random variable representing crime rate (crimes per 1000 population). A random sample of six Denver neighborhoods gave the following information.
x | 30 | 3 | 11 | 17 | 7 | 6 |
y | 170 | 35 | 132 | 127 | 69 | 53 |
Σx = 74; Σy = 586; Σx2 = 1,404; Σy2 = 71,248; Σxy = 9,617
(a) Find x, y, b, and the equation of the least-squares line. (Round your answers for x and y to two decimal places. Round your least-squares estimates to three decimal places.)
x | = | |||||
y | = | |||||
b | = | |||||
+ x(c) Find the sample correlation coefficient r and the coefficient of determination. (Round your answers to three decimal places.)
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a)]
X̅=ΣX/n = | 12.33 |
Y̅=ΣY/n = | 97.67 |
b=4.864
ŷ = | 37.682+4.864x |
c)
r=Cov/(Sx*Sy)= | 0.911 |
coefficient of determination r2 = | 0.829 |
percentage of variation in y is explained by the least-squares model =82.9 %
d)
predicted value =37.682+4.864*15= | 110.6 |
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