Question

Fifty-nine items are randomly selected from a population of 650 items. The sample mean is 37,...

Fifty-nine items are randomly selected from a population of 650 items. The sample mean is 37, and the sample standard deviation 2. Develop a 90% confidence interval for the population mean. (Round the final answers to 2 decimal places.)            

    

The confidence interval is between       and

Homework Answers

Answer #1

Solution :

Given that,

t /2,df = 1.672

Margin of error = E = t/2,df * (s /n)

= 1.672 * (2 / 59)

Margin of error = E = 0.44

The 90% confidence interval estimate of the population mean is,

- E < < + E

37 - 0.44 < < 37 + 0.44

36.56 < < 37.44

The confidence interval is between 36.56 and 37.44

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Thirty-seven items are randomly selected from a population of 390 items. The sample mean is 36,...
Thirty-seven items are randomly selected from a population of 390 items. The sample mean is 36, and the sample standard deviation 10. Develop a 90% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 2 decimal places.)   The confidence interval is between  and  .
Thirty items are randomly selected from a population of 320 items. The sample mean is 29,...
Thirty items are randomly selected from a population of 320 items. The sample mean is 29, and the sample standard deviation 3. Develop a 80% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 2 decimal places.)   The confidence interval is between and
A sample of 40 observations is selected from a normal population where the population standard deviation...
A sample of 40 observations is selected from a normal population where the population standard deviation is 25. The sample mean is 75. a. Determine the standard error of the mean. (Round the final answer to 3 decimal places.) The standard error of the mean is  . b. Determine the 90% confidence interval for the population mean. (Round the z-value to 2 decimal places. Round the final answers to 3 decimal places.) The 90% confidence interval for the population mean is...
A sample of 23 observations is selected from a normal population where the sample standard deviation...
A sample of 23 observations is selected from a normal population where the sample standard deviation is 4.95. The sample mean is 16.90.   a. Determine the standard error of the mean. (Round the final answer to 2 decimal places.) The standard error of the mean is _______ . b. Determine the 90% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 3 decimal places.) The 90% confidence interval for the population...
A sample of 25 observations is selected from a normal population where the population standard deviation...
A sample of 25 observations is selected from a normal population where the population standard deviation is 32. The sample mean is 77.   a. Determine the standard error of the mean. (Round the final answer to 3 decimal places.) The standard error of the mean is . b. Determine the 95% confidence interval for the population mean. (Round the z-value to 2 decimal places. Round the final answers to 3 decimal places.) The 95% confidence interval for the population mean...
A sample of 29 observations is selected from a normal population where the population standard deviation...
A sample of 29 observations is selected from a normal population where the population standard deviation is 40. The sample mean is 89.   a. Determine the standard error of the mean. (Round the final answer to 3 decimal places.) The standard error of the mean is  . b. Determine the 98% confidence interval for the population mean. (Round the z-value to 2 decimal places. Round the final answers to 3 decimal places.) The 98% confidence interval for the population mean is...
A sample of 28 observations is selected from a normal population where the sample standard deviation...
A sample of 28 observations is selected from a normal population where the sample standard deviation is 5.00. The sample mean is 16.95.   a. Determine the standard error of the mean. (Round the final answer to 2 decimal places.) The standard error of the mean is. b. Determine the 95% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 3 decimal places.) The 95% confidence interval for the population mean is...
A sample of 25 observations is selected from a normal population where the sample standard deviation...
A sample of 25 observations is selected from a normal population where the sample standard deviation is 4.85. The sample mean is 16.80.   a. Determine the standard error of the mean. (Round the final answer to 2 decimal places.) The standard error of the mean is            . b. Determine the 95% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 3 decimal places.) The 95% confidence interval for the population...
A sample of 28 observations is selected from a normal population where the sample standard deviation...
A sample of 28 observations is selected from a normal population where the sample standard deviation is 4.40. The sample mean is 16.40.   a. Determine the standard error of the mean. (Round the final answer to 2 decimal places.) The standard error of the mean is            . b. Determine the 98% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 3 decimal places.) The 98% confidence interval for the population...
A random sample of fifty dash nine ​200-meter swims has a mean time of 3.14 minutes...
A random sample of fifty dash nine ​200-meter swims has a mean time of 3.14 minutes and the population standard deviation is 0.09 minutes. Construct a 90​% confidence interval for the population mean time. Interpret the results. The 90​% confidence interval is