Thirty-seven items are randomly selected from a population of 390 items. The sample mean is 36, and the sample standard deviation 10. Develop a 90% confidence interval for the population mean. (Round the t-value to 3 decimal places. Round the final answers to 2 decimal places.)
The confidence interval is between and .
Solution :
Given that,
t /2,df = 1.688
Margin of error = E = t/2,df * (s /n)
= 1.688 * (10 / 37)
Margin of error = E = 2.78
The 90% confidence interval estimate of the population mean is,
- E < < + E
36 - 2.78 < < 36 + 2.78
33.22 < < 38.78
The confidence interval is between 33.22 and 38.78
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