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Use the counting techniques from the last chapter. A bag contains three red marbles, three green...

Use the counting techniques from the last chapter. A bag contains three red marbles, three green ones, one fluorescent pink one, four yellow ones, and three orange ones. Suzan grabs four at random. Find the probability of the indicated event.

She gets one of each color other than fluorescent pink, given that she gets the fluorescent pink one.

Math   Statistics-And-Probability   
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Answer #1

let us assume balls of same colour are also different (this wont affect our answer because probability is a ratio)

no of cases of one flourescent pink = p =1C1*13C3 = 286 without any condition

for fourescent pink with one of each colour other than flourescent pink we have 4 cases-

1. red,green,yellow : p1= 3C1*3C1*4C1=36

2. red,green,orance : p2=3C1*3C1*3C1=27

3. red, yellow,orange :p3= 3C1*4C1*3C1=36

4. green,yellow,orange :p4=3C1*4C1*3C1=36

BY BAYES' THEOROM OF PROBABILITY

OUR ANSWER IS =( p1+p2+p3+p4)/p= (36+27+36+36)/286=135/286=0.472

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