PART A) Recall from Example 1 that whenever Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing three red marbles, four green ones, three white ones, and two purple ones. She grabs five of them. Find the probability of the following event, expressing it as a fraction in lowest terms. HINT [See Example 1.]
She has two red ones and one of each of the other colors.
PART B) Recall from Example 1 that whenever Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing three red marbles, four green ones, two white ones, and two purple ones. She grabs five of them. Find the probability of the following event, expressing it as a fraction in lowest terms. HINT [See Example 1.]
She has two green ones and one of each of the other colors.
A) Probability that 2 red and one each of the other 3 colours is
computed here as:
= Number of ways to select 2 red from 3 red marbles * Number of
ways to select 1 green from 4 green marbles * Number of ways to
select 1 white from 3 white marbles * Number of ways to select 1
purple from 2 purple marbles / Total number of ways to select 5
marbles from 12 marbles
Therefore 1/11 us the required probability here.
B) Here again we use the same concept in the above problem to get the required probability as:
Therefore 12/77 is the required probability here.
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