e. If it is known that a packaged salad has excess moisture, what is the probability that it came from Supplier B?
f. If it is known that a packaged salad has excess moisture, what is the probability that it came from Supplier C?
a) P(supplier C and excess moisture) = P(excess moisture | supplier C) * P(Supplier C) = 0.1 * 0.4 = 0.04
B) P(excess moisture) = 0.12 * 0.2 + 0.08 * 0.4 + 0.1 * 0.4 = 0.096
C) P(excess moisture | B) = 0.08
D) P(A | excess moisture) = P(Excess moisture | A) * P(A)/P(excess moisture) = (0.12 * 0.2)/0.096 = 0.25
E) P(B | excess moisture) = P(Excess moisture | B) * P(B)/P(excess moisture) = (0.08 * 0.4)/0.096 = 0.3333
F) P(C | excess moisture) = P(excess moisture | C) * P(C)/P(excess moisture) = (0.1 * 0.4)/0.096 = 0.4167
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