The distribution of a random variable X is symmetric, with a
mean of 500 and a standard
Deviation of 10. You are asked to provide two numbers such that
about 68% of the values
Of X are between the two numbers. The two numbers are:
a. (400, 600)
b. (490, 510)
c. (480,520)
d. Can’t tell
Given that,
mean = = 500
standard deviation = = 10
middle 68% of score is
P(-z < Z < z) = 0.68
P(Z < z) - P(Z < -z) = 0.68
2 P(Z < z) - 1 = 0.68
2 P(Z < z) = 1 + 0.68 = 1.68
P(Z < z) = 1.68 / 2 = 0.84
P(Z <0.99 ) = 0.84
z ± 0.99 using z table
Using z-score formula
x= z * +
x= ± 0.99*10+500
x= 490 , 510
correct option b. (490, 510)
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