Question

A random sample of 25 values is drawn from a mound_shaped symmetric distribution. The sample mean is 10 and the sample standard deviation is 2.

Use α = 0.05 to test the claim that the population mean is different from 9.5.

A) Check the requirements.

B) Set up the hypothesis.

C) Compute the test statistic.

D) Find the p-value.

E) Do we reject or do not reject Ho?

Answer #1

*Given,*

*X_bar = 10*

*s= 2*

*n=25*

*a) Hypothesis :*

*H _{0} :
=9.5*

*H _{1} :
9.5*

*b) test statistic*

*t = (x_bar -
)/(s/n)*

*= (10-9.5)/(2/25)*

*t = 1.25*

*3) Df = n-1 = 25-1 = 24*

*p value for t test statistic with 24 degree of freedom is
0.2234.*

*P value = 0.2234*

*4) conclusion:*

*P value (0.2234) is greater than 0.05, hence do not reject
null hypothesis.*

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