Question

Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7...

Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed well.
Two are drawn.
What are the odds that the sum of the numbers on the two selected slips is not 6?

Homework Answers

Answer #1

Since chips are drawn at random so possible number of outcomes is

Following table shows all possible outcoems and corresponding sum :

Outcomes Sum
1 2 3
1 3 4
1 4 5
1 5 6
1 6 7
1 7 8
2 3 5
2 4 6
2 5 7
2 6 8
2 7 9
3 4 7
3 5 8
3 6 9
3 7 10
4 5 9
4 6 10
4 7 11
5 6 11
5 7 12
6 7 13

Out of 21 outcomes, 2 shows sum 6.

That is outcome in favor are 21-2=19 and against are 2.

The odds are the sum of the numbers on the two selected slips is not 6 is 19 : 2.

Answer: 19 : 2

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