Let us move to linear programming
2.1 The objective function is:
2.2 The budget constraint is:
a. R + TV <= 70000
b. R/1000 + TV/1000 <= 70
c. R + TV <= 70
2.3 The constraint on the combined number of ads is:
a. (R*250 + TV*1500)/70 >=
75
b. 1000R/250 + 1000TV/1500 <= 75
c. R/250 + TV/1500
<=70000/75
d. (R+TV)/(250+1500) <=75
2.4 The constraint (or constraints) on the amounts spent on the two media is:
a. We need two constraints: R – TV <= 15, and TV – R <= 15.
b. We can either use R – TV <= 15, or TV – R <= 15, but not both.
c. We need two constraints: R <= 15 and TV >= 15.
d. R – TV >= 15, and TV – R >= 15
Ans :- We define R as the amount in thousand dollars on radio ads
and TV as the amount in thousand dollars on TV ads
2.1 The objective function is to maximise the number of new customers
Max 70*R + 105*TV
2.2 the budget constraitn is that it cannot exceed 70000
R + TV <= 70 (since R and TV already measured in thousand of dollars)
2.3 The constraint on the combined number of ads is: they should not exceed 75 combinedly
1000R/250 + 1000TV/1500 <= 75
2.4 The constraint (or constraints) on the amounts spent on the two media is:The amount spent on radio ads, and the amount spent on TV ads cannot differ from one another by more than $15000.
We need two constraints: R – TV <= 15, and TV – R <= 15.
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