Question

Use the data in the following​ table, which lists​ drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the table. ​Drive-thru Restaurant A B C D Order Accurate 327 264 250 133 Order Not Accurate 32 55 38 16 If one order is​ selected, find the probability of getting an order from Restaurant A or an order that is accurate. Are the events of selecting an order from Restaurant A and selecting an accurate order disjoint​ events? The probability of getting an order from Restaurant A or an order that is accurate is nothing . ​(Round to three decimal places as​ needed.)

Answer 1

solution:   Restaurant A B C D

Order Accurate 327 264 250 133

Order Not Accurate 32 55 38 16

=> the probability of getting an order from Restaurant A or an order that is accurate = 0.902

P(Restaurant A) = 359 /1115,

P(accurate) = 974/ 1115

P(restaurant A and order accurate ) = 327/ 1115

So the probability of getting an order that is not accurate or is from Restaurant C is

P( restaurant A or order accurate) = P(Restaurant A)+ P(order accurate) - P(restaurant A and order accurate )

= (359/ 1115) + ( 974/ 1115) - (327/1115) = 0.902

Since P( restaurant A or order accurate) is not equal to zero so the events of selecting an order that is accurate and selecting an order from Restaurant A are not disjoint events.