An exam consists of 10 true-or-false questions. If a student guesses at every answer, what is the probability that he or she will answer exactly 6 questions correctly? (Round your answer to three decimal places.)
X ~ Bin(n,p)
Where n = 10 , p = 0.5
np = 10 * 0.5 = 5 >= 5
n(1-p) = 10 * 0.5 = 5 >= 5
Since np >= 5 and n(1-p) >= 5 , normal approximation is appropriate.
Mean = np = 10 * 0.5 = 5
Standard deviation = sqrt [ np(1-p) ]
= sqrt [ 10 * 0.5 * 0.5 ]
= 1.5811
Using normal approximation,
P(X < x) = P(Z < x - Mean / SD)
With continuity correction,
P(X = 6) = P(5.5 < X < 6.5)
= P(X < 6.5) - P(X < 5.5)
= P(Z < (6.5 - 5) / 1.5811) - P(Z < (5.5 - 5) / 1.5811)
= P(Z < 0.95) - P(Z < 0.32)
= 0.8289 - 0.6255
= 0.203
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