Let W be a random variable giving the number of
tails
minus the number of
heads
in three tosses of a coin. Assuming that a
tail
is
half
as likely to occur, find the probability distribution of the random variable W.
Complete the following probability distribution of W.
When a coin is tossed thrice, S = {hhh, hht, hth, htt, ttt, tth, tht, thh}
Let P(h) = p then P(t) = p/2
p + p/2 = 1, so p = 2/3
Thus, P(h) = 2/3 and P(t) = 1/3
W = number of tails – number of heads
Event | n(t) | n(h) | W = n(t) - n(h) | P(W) |
hhh | 0 | 3 | -3 | (2/3)(2/3)(2/3) = 8/27 |
hht | 1 | 2 | -1 | (2/3)(2/3)(1/3) = 4/27 |
hth | 1 | 2 | -1 | (2/3)(1/3)(2/3) = 4/27 |
htt | 2 | 1 | 1 | (2/3)(1/3)(1/3) = 2/27 |
ttt | 3 | 0 | 3 | (1/3)(1/3)(1/3) = 1/27 |
tth | 2 | 1 | 1 | (1/3)(1/3)(2/3) = 2/27 |
tht | 2 | 1 | 1 | (1/3)(2/3)(1/3) = 2/27 |
thh | 1 | 2 | -1 | (1/3)(2/3)(2/3) = 4/27 |
W | P(W) |
-3 | 8/27 |
-1 | 4/27 + 4/27 + 4/27 = 12/27 |
1 | 2/27 + 2/27 + 2/27 = 6/27 |
3 | 1/27 |
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