Question

Assume that the distribution of squirrel weights are normally distributed with mean=1.7 lbs and standard dev.= 0.5 lbs. Suppose we want to find the proportion of squirrels that weigh between 0.8 and 1.2 lbs. Suppose we want to find the proportion of squirrels that weigh between 0.8 and 1.2 lbs. Standardize the weights of 0.8 lbs and 1.2 lbs. Write the z-scores corresponding to the two weights below.

Answer 1

Given data

mean weight of the squirrel

Standard deviation

Now we have to find the proportion of the squirrel weight between 0.8 to 1.2

Now for X=0.8

Z score for this X=0.8

Now from the standard probability distribution table the probability value less than  Z = - 1.8

P(X<0.8)=0.0359

Now for X=1.2

Z score for this will be

Now from the standard probability distribution table the probability value less than  Z = - 1

P(X<1.2)=0.1587

So the probability value for the weight of the squirrel between 0.8 to 1.2 will be