Question

Sample Size for 90% CL, E = 2.1 and σ = 19

Sample Size for 90% CL, E = 2.1 and σ = 19

Homework Answers

Answer #1

Solution :

Given that,

standard deviation = = 19

margin of error = E = 2.1

At 90% confidence level the z is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

Z/2 = Z0.05 = 1.645

Sample size = n = ((Z/2 * ) / E)2

= ((1.645 * 19) / 2.1)2

= 221.51 = 222  

Sample size = 222

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