Sample Size for 90% CL, E = 2.1 and σ = 19
Solution :
Given that,
standard deviation = = 19
margin of error = E = 2.1
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Sample size = n = ((Z/2 * ) / E)2
= ((1.645 * 19) / 2.1)2
= 221.51 = 222
Sample size = 222
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