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The weights of 22 randomly selected mattresses were found to have a standard deviation of 3.17. Construct the 95% confidence interval for the population standard deviation of the weights of all mattresses in this factory. Round your answers to two decimal places.
df = n - 1 = 22 - 1 = 21
Chi square critical values at 0.05 level with 21 df = 10.283 , 35.479
95% confidence interval for is
Sqrt [ (n-1) S2 / /2] < < Sqrt [ (n-1) S2 / 1-/2]
Sqrt [ (22 -1) * 3.172 / 35.479 ] < < Sqrt [ (22 -1) * 3.172 / 10.283]
2.44 < < 4.53
95% CI is ( 2.44 , 4.53 )
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