Question

Henrique​ Correa's bakery prepares all its cakes between 4 A.M.and 6 A.M.so they will be fresh when customers arrive.​ Day-old cakes are virtually always​ sold, but at a​ 50% discount off the regular ​$16 price. The cost of baking a cake is ​$10​, and demand is estimated to be normally​ distributed, with a mean of 25 and a standard deviation of 7. What is the optimal stocking​ level? Refer to the standard normal table LOADING... for​ z-values.

The optimal stocking level for the bakery is

nothing cakes ​(round your response to the nearest whole​ number).

Z

0.00

0.01

0.02

  

0.5000

0.5040

0.5080

0.5120

0.5160

0.5199

0.5239

0.5279

0.5319

0.5359

0.1

0.5398

0.5438

0.5478

0.5517

0.5557

0.5596

0.5636

0.5675

0.5714

0.5754

0.2

0.5793

0.5832

0.5871

0.5910

0.5948

0.5987

0.6026

0.6064

0.6103

0.6141

0.3

0.6179

0.6217

0.6255

0.6293

0.6331

0.6368

0.6406

0.6443

0.6480

0.6517

0.4

0.6554

0.6591

0.6628

0.6664

0.6700

0.6736

0.6772

0.6808

0.6844

0.6879

0.5

0.6915

0.6950

0.6985

0.7019

0.7054

0.7088

0.7123

0.7157

0.7190

0.7224

0.6

0.7258

0.7291

0.7324

0.7357

0.7389

0.7422

0.7454

0.7486

0.7518

0.7549

0.7

0.7580

0.7612

0.7642

0.7673

0.7704

0.7734

0.7764

0.7794

0.7823

0.7852

0.8

0.7881

0.7910

0.7939

0.7967

0.7996

0.8023

0.8051

0.8079

0.8106

0.8133

0.9

0.8159

0.8186

0.8212

0.8238

0.8264

0.8289

0.8315

0.8340

0.8365

0.8389

1.0

0.8413

0.8438

0.8461

0.8485

0.8508

0.8531

0.8554

0.8577

0.8599

0.8621

1.1

0.8643

0.8665

0.8686

0.8708

0.8729

0.8749

0.8770

0.8790

0.8810

0.8830

1.2

0.8849

0.8869

0.8888

0.8907

0.8925

0.8944

0.8962

0.8980

0.8997

0.9015

1.3

0.9032

0.9049

0.9066

0.9082

0.9099

0.9115

0.9131

0.9147

0.9162

0.9177

1.4

0.9192

0.9207

0.9222

0.9236

0.9251

0.9265

0.9279

0.9292

0.9306

0.9319

1.5

0.9332

0.9345

0.9357

0.9370

0.9382

0.9394

0.9406

0.9418

0.9430

0.9441

1.6

0.9452

0.9463

0.9474

0.9485

0.9495

0.9505

0.9515

0.9525

0.9535

0.9545

1.7

0.9554

0.9564

0.9573

0.9582

0.9591

0.9599

0.9608

0.9616

0.9625

0.9633

1.8

0.9641

0.9649

0.9656

0.9664

0.9671

0.9678

0.9686

0.9693

0.9700

0.9706

1.9

0.9713

0.9719

0.9726

0.9732

0.9738

0.9744

0.9750

0.9756

0.9762

0.9767

2.0

0.9773

0.9778

0.9783

0.9788

0.9793

0.9798

0.9803

0.9808

0.9812

0.9817

2.1

0.9821

0.9826

0.9830

0.9834

0.9838

0.9842

0.9846

0.9850

0.9854

0.9857

2.2

0.9861

0.9865

0.9868

0.9871

0.9875

0.9878

0.9881

0.9884

0.9887

0.9890

2.3

0.9893

0.9896

0.9898

0.9901

0.9904

0.9906

0.9909

0.9911

0.9913

0.9916

2.4

0.9918

0.9920

0.9922

0.9925

0.9927

0.9929

0.9931

0.9932

0.9934

0.9936

2.5

0.9938

0.9940

0.9941

0.9943

0.9945

0.9946

0.9948

0.9949

0.9951

0.9952

2.6

0.9953

0.9955

0.9956

0.9957

0.9959

0.9960

0.9961

0.9962

0.9963

0.9964

2.7

0.9965

0.9966

0.9967

0.9968

0.9969

0.9970

0.9971

0.9972

0.9973

0.9974

2.8

0.9974

0.9975

0.9976

0.9977

0.9977

0.9978

0.9979

0.9980

0.9980

0.9981

2.9

0.9981

0.9982

0.9983

0.9983

0.9984

0.9984

0.9985

0.9985

0.9986

0.9986

3.0

0.9987

0.9987

0.9987

0.9988

0.9988

0.9989

0.9990

0.9989

0.9990

0.9990

Answer 1

This problem will be solved using Newsvendor model

Given are following data :

Average demand = m = 25

Standard deviation of demand = Sd = 7

Sale price = P = $16/ unit

Cost of cake = C = $10 / unit

Salvage price = S = 50% of $16 = $8 / unit

Thus ,

Cost of underordering = Cu = P – C = $16 - $10 = $6 / unit

Cost of overordering = Co = C – S = $ 10 - $ 8 = $ 2/ unit

Therefore,

Critical ratio = Cu/ ( Cu + Co) = 6/ ( 6 + 2) = 6/8 = 0.75

Critical ratio is the probability of optimum stocking level . Corresponding Z value for such optimum stocking level = NORMSINV ( 0.75 ) = 0.6745

Therefore , Optimum stocking level for the Bakery

= m + Z x Sd

= 25 + 0.6745x 7

= 25 + 4.72

= 29.72 ( 30 rounding to next higher whole number )

OPTIMUM STOCKING LEVEL FOR THE BAKERY = 30