Run a regression analysis on the following data set, where yy is the final grade in a math class and xx is the average number of hours the student spent working on math each week.
hours/week x |
Grade y |
---|---|
5 | 56 |
6 | 51.4 |
6 | 66.4 |
9 | 65.6 |
11 | 74.4 |
11 | 64.4 |
11 | 76.4 |
12 | 78.8 |
13 | 75.2 |
20 | 100 |
State the regression equation y=m⋅x+by=m⋅x+b, with constants
accurate to two decimal places.
What is the predicted value for the final grade when a student
spends an average of 9 hours each week on math?
Grade = Round to 1 decimal place.
X | Y | XY | X^2 | Y^2 |
5 | 56 | 280 | 25 | 3136 |
6 | 51.4 | 308.4 | 36 | 2641.96 |
6 | 66.4 | 398.4 | 36 | 4408.96 |
9 | 65.6 | 590.4 | 81 | 4303.36 |
11 | 74.4 | 818.4 | 121 | 5535.36 |
11 | 64.4 | 708.4 | 121 | 4147.36 |
11 | 76.4 | 840.4 | 121 | 5836.96 |
12 | 78.8 | 945.6 | 144 | 6209.44 |
13 | 75.2 | 977.6 | 169 | 5655.04 |
20 | 100 | 2000 | 400 | 10000 |
From the above table and formula we get the value are as:
n | 10 |
sum(XY) | 7867.60 |
sum(X) | 104.00 |
sum(Y) | 708.60 |
sum(X^2) | 1254.00 |
sum(Y^2) | 51874.44 |
b | 2.89 |
a | 40.81 |
ycap = mx + b
yacp = 2.89 * x + 40.81
when x = 9
Predicted value = 2.89 * 9 + 40.81
= 66.8
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