Run a regression analysis on the following bivariate set of data with y as the response variable.
x | y |
---|---|
28.8 | 90.1 |
30.6 | 139.6 |
12.6 | 42.2 |
18.1 | 94.8 |
13.9 | 28.5 |
31.9 | 102.4 |
-3.9 | -13.4 |
16.7 | 57.1 |
11 | 55.8 |
16.8 | 76.3 |
31.7 | 80.1 |
43.5 | 123.8 |
Find the correlation coefficient and report it accurate to three
decimal places.
r =
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a
percentage accurate to one decimal place. (If the answer is
0.84471, then it would be 84.5%...you would enter 84.5 without the
percent symbol.)
r² = %
Based on the data, calculate the regression line (each value to
three decimal places)
y = x +
Predict what value (on average) for the response variable will be
obtained from a value of 11.1 as the explanatory variable.
What is the predicted response value? (Report answer accurate to
one decimal place.)
y =
b) Coefficient of Determination(R-squared):
It gives the measure of how close the data points are to the best
fit line. In other words, it gives the proportion of variability in
dependent variable that can be explained by the independent
variable. Higher the Rsquared value, better the model is.
d) x = 11.1
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