Question

10. Use the weights of cans of generic soda as sample​ one, and use the weights...

10. Use the weights of cans of generic soda as sample​ one, and use the weights of cans of the diet version of that soda as sample two. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Construct a 90​% confidence interval estimate of the difference between the mean weight of the cans of generic soda and the mean weight of cans of the diet version of that soda. Does there appear to be a difference between the mean​ weights?

Weight_of_Generic_Soda   Weight_of_Diet_Soda
0.8152   0.8666
0.8494   0.8509
0.8568   0.8327
0.8569   0.8136
0.8621   0.8066
0.8978   0.8167
0.8979   0.8095
0.8896   0.8037
0.8919   0.8197
0.8136   0.8635
0.8165   0.8615
0.8104   0.8633
0.8461   0.8608
0.8273   0.8593
0.8232   0.8664
0.8347   0.8592
0.8494   0.8727
0.8385   0.8552
0.8437   0.8744
0.8441   0.8396
0.8436   0.8165
0.8854   0.8152
0.8705   0.8443
0.8439   0.8372
0.8415   0.8025
0.8517   0.8216
0.8008   0.8096
0.8737   0.8187
0.8253   0.8482
0.8563   0.8404
0.8539   0.8225
0.8533   0.8213
0.8649   0.8238
0.8583   0.8072
0.8589   0.8093
0.8677   0.8177

Assume that population 1 is the generic soda and population 2 is the diet soda.

The 90​% confidence interval is ____ ounces <µ1-µ2<___ ounces.

​(Round to four decimal places as​ needed.)

Does there appear to be a difference between the mean​ weights?

The mean weight for the generic soda appears to be (greater than,less than,equal to) the mean weight for the diet variety because the confidence interval contains (only positive values, zero, only negative values.)

Homework Answers

Answer #1

Weight_of_Generic_Soda (X1 )   Weight_of_Diet_Soda (X2 )

0.8136 0.8635
0.8165 0.8615
0.8104 0.8633
0.8461 0.8608
0.8152 0.8666
0.8494 0.8509
0.8568 0.8327
0.8569 0.8136
0.8621 0.8066
0.8978 0.8167
0.8979 0.8095
0.8896 0.8037
0.8919 0.8197
0.8273 0.8593
0.8232 0.8664
0.8347 0.8592
0.8494 0.8727
0.8385 0.8552
0.8437 0.8744
0.8441 0.8396
0.8436 0.8165
0.8854 0.8152
0.8705 0.8443
0.8439 0.8372
0.8415 0.8025
0.8517 0.8216
0.8008 0.8096
0.8737 0.8187
0.8253 0.8482
0.8563 0.8404
0.8539 0.8225
0.8533 0.8213
0.8649 0.8238
0.8583 0.8072
0.8589 0.8093
0.8677 0.8177

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Data on the weights​ (lb) of the contents of cans of diet soda versus the contents...
Data on the weights​ (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed​ populations, and do not assume that the population standard deviations are equal. Complete parts​ (a) and​ (b) below. Use a 0.01 significance level for both parts. a) the test statistic, t is ____ (Round two decimals...
A simple random sample of 31 cans of generic soda had their caffeine levels measured, in...
A simple random sample of 31 cans of generic soda had their caffeine levels measured, in milligrams per 12 ounce serving. The data is given below. Find the 99% confidence interval estimate of the mean amount of caffeine in the entire population of this generic soda. 34           35           35           36           36           36           38           38           38           38           38           39           40 40     41           42 43           43          ...
6. A simple random sample of 31 cans of generic soda had their caffeine levels measured,...
6. A simple random sample of 31 cans of generic soda had their caffeine levels measured, in milligrams per 12 ounce serving. The data is given below. Find the 99% confidence interval estimate of the mean amount of caffeine in the entire population of this generic soda. 34 35 35 36 36 36 38 38 38 38 38 39 40 40 41 42 43 43 45 45 46 46 47 50 50 51 52 53 55 56 60
Given that the volume of soda cans varies normally with a mean of 12.0 fluid ounces...
Given that the volume of soda cans varies normally with a mean of 12.0 fluid ounces and a known standard deviation of 1.0 fluid ounces: A. Find the probability of the mean volume of 16 soda cans to be between 11.5 and 12.5 fluid ounces. B. Assuming that an eight-pack is rejected if the mean volume is in the bottom 7%, find this cut-off volume, ie. and upper-limit. C. Construct a 94.2% confidence interval for the mean volume of 9...
You measure 47 textbooks' weights, and find they have a mean weight of 74 ounces. Assume...
You measure 47 textbooks' weights, and find they have a mean weight of 74 ounces. Assume the population standard deviation is 10.3 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places I am 90% confident that the mean weight of textbooks is between  and ounces.
1) You measure 25 textbook' weights, and find they have a mean weight of 60 ounces....
1) You measure 25 textbook' weights, and find they have a mean weight of 60 ounces. Assume the population standard deviation is 9.2 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean backpack weight. Give your answer as a decimal, to two places a) You measure 46 textbooks' weights, and find they have a mean weight of 48 ounces. Assume the population standard deviation is 7.8 ounces....
You measure 22 dogs' weights, and find they have a mean weight of 42 ounces. Assume...
You measure 22 dogs' weights, and find they have a mean weight of 42 ounces. Assume the population standard deviation is 2.2 ounces. Based on this, construct a 90% confidence interval for the true population mean dog weight.
you measure 25 turtles weights, and find they have a mean weight of 45 ounces. assume...
you measure 25 turtles weights, and find they have a mean weight of 45 ounces. assume the population standard deviation is 4.2 ounces. Based on this, construct a 90% confidence interval for the true population mean turtle weight.
You measure 39 textbooks' weights and find they have a mean weight of 44 ounces. Assume...
You measure 39 textbooks' weights and find they have a mean weight of 44 ounces. Assume the population standard deviation is 12.7 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places I am 99% confident that the mean weight of textbooks is between and ounces. You measure 46 textbooks' weights, and find they have a mean weight of 38 ounces. Assume the population standard deviation...
You measure 26 turtles' weights, and find they have a mean weight of 39 ounces. Assume...
You measure 26 turtles' weights, and find they have a mean weight of 39 ounces. Assume the population standard deviation is 12.8 ounces. Based on this, construct a 90% confidence interval for the true population mean turtle weight. Give your answers as decimals, to two places ±±  ounces