A transect is an archaeological study area that is 1/5 mile wide and 1 mile long. A site in a transect is the location of a significant archaeological find. Let x represent the number of sites per transect. In a section of Chaco Canyon, a large number of transects showed that x has a population variance σ2 = 42.3. In a different section of Chaco Canyon, a random sample of 24 transects gave a sample variance s2 = 45.1 for the number of sites per transect. Use a 5% level of significance to test the claim that the variance in the new section is greater than 42.3. Find a 95% confidence interval for the population variance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ2 = 42.3; H1: σ2 > 42.3Ho: σ2 = 42.3; H1: σ2 ≠ 42.3 Ho: σ2 = 42.3; H1: σ2 < 42.3Ho: σ2 > 42.3; H1: σ2 = 42.3
(b) Find the value of the chi-square statistic for the sample.
(Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the original
distribution?
We assume a binomial population distribution.We assume a exponential population distribution. We assume a normal population distribution.We assume a uniform population distribution.
(c) Find or estimate the P-value of the sample test
statistic.
P-value > 0.1000.050 < P-value < 0.100 0.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.010P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis?
Since the P-value > α, we fail to reject the null hypothesis.Since the P-value > α, we reject the null hypothesis. Since the P-value ≤ α, we reject the null hypothesis.Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 5% level of significance, there is insufficient evidence to conclude conclude that the variance is greater in the new section.At the 5% level of significance, there is sufficient evidence to conclude conclude that the variance is greater in the new section.
(f) Find the requested confidence interval for the population
variance. (Round your answers to two decimal places.)
lower limit | |
upper limit |
Interpret the results in the context of the application.
We are 95% confident that σ2 lies within this interval.We are 95% confident that σ2 lies outside this interval. We are 95% confident that σ2 lies below this interval.We are 95% confident that σ2 lies above this interval.
The statistical software output for this problem is:
Hence,
a) Level of significance = 0.05
Hypotheses: Ho: σ2 = 42.3; H1: σ2 > 42.3
b) Test statistic = 24.52
Degrees of freedom = 23
We assume a normal population distribution.
c) P-value > 0.100
d) Since the P-value > α, we fail to reject the null hypothesis.
e) At the 5% level of significance, there is insufficient evidence to conclude conclude that the variance is greater in the new section.
f) 95% confidence interval:
Lower limit = 27.24
Upper limit = 88.74
We are 95% confident that σ2 lies within this interval.
Get Answers For Free
Most questions answered within 1 hours.