11) α = 0.05 for a two-tailed test.
A) ±1.764 B) ±2.575 C) ±1.96 D) ±1.645
12) α = 0.09 for a right-tailed test.
A) ±1.96 B) 1.96 C) 1.34 D) ±1.34
13) α = 0.05 for a left-tailed test.
A) -1.96 B) ±1.96 C) ±1.645 D) -1.645
16) Find the critical value for a right-tailed test with α = 0.01
and n = 75.
A) 2.33 B) 1.645 C) 2.575 D) 1.96
17) Find the critical value for a two-tailed test with α = 0.01 and
n = 30.
A) ±1.645 B) ±2.575 C) ±1.96 D) ±2.33
18) Find the critical value for a left-tailed test with α = 0.05
and n = 48.
A) -1.96 B) -2.575 C) -1.645 D) -2.33
19) Find the critical value for a two-tailed test with α = 0.10 and
n = 100.
A) ±2.33 B) ±1.96 C) ±2.575 D) ±1.645
14) α = 0.1 for a two-tailed test.
A) ±1.645 B) ±1.4805 C) ±2.052 D) ±2.33
15) α = 0.08; H1 is μ ≠ 3.24
A) 1.75 B) ±1.75 C) 1.41 D) ±1.41
Please show work for 11 and 16. a letter for the answer for the rest is fine as I can check my work.
Answer)
We need to use standard normal z table to estimate the critical values
11)
Answer)
Test is two tailed.
So, first we need to divide the given significance level alpha in to two equal parts.
0.05/2 = 0.025
From z table, P(z<-1.96) = P(z>1.96) = 0.025
So, critical values are -1.96 and 1.96
12)
We have a right tailed test with 0.09 alpha.
From z table, P(z>1.34) = 0.09
So, critical value is 1.34.
13)
Left tailed test with 0.05 alpha.
From z table, P(z<-1.645) = 0.05.
16)
Here we need to use t table to estimate the critical value.
As n is given.
Degrees of freedom is = n-1 = 14
For 14 dof and 0.01 alpha, critical value t from t distribution table is 2.33
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