QUESTION 8
Suppose a student guesses that 75% of RCSJ students have been to at least one professional sporting event in Philadelphia. She gathers data and finds that 189 of the 290 RCSJ students surveyed had been to at least one professional sporting event in Philadelphia. She would like to conduct a hypothesis test to see if her guess was reasonable. After seeing her results, if this student constructs a confidence interval with her sample data, what should she find?
A. |
Her guess of 75% will be within her interval. |
|
B. |
Her guess of 75% will be outside her interval. |
QUESTION 13
Jon reads that 76% of Americans prefer Coke over Pepsi. He works at a local restaurant and decides to poll his customers there about their soda preference. He finds that 120 out of 150 customers surveyed prefer Coke. He would like to conduct a test of hypothesis to see if there is a significant difference between customers at his restaurant and the national results for all Americans, in terms of their preference for Coke over Pepsi. Calculate his test statistic.
A. |
1.96 |
|
B. |
1.55 |
|
C. |
1.15 |
|
D. |
0.04 |
QUESTION 14
Jon reads that 76% of Americans prefer Coke over Pepsi. He works at a local restaurant and decides to poll his customers there about their soda preference. He finds that 120 out of 150 customers surveyed prefer Coke. He would like to conduct a test of hypothesis to see if there is a significant difference between customers at his restaurant and the national results for all Americans, in terms of their preference for Coke over Pepsi. If Jon is using a 90% level of confidence (alpha level of 0.10), what is the critical value that would mark off his rejection region?
A. |
1.28 |
|
B. |
2.33 |
|
C. |
1.645 |
|
D. |
2.575 |
QUESTION 15
Jon reads that 76% of Americans prefer Coke over Pepsi. He works at a local restaurant and decides to poll his customers there about their soda preference. He finds that 120 out of 150 customers surveyed prefer Coke. He would like to conduct a test of hypothesis to see if there is a significant difference between customers at his restaurant and the national results for all Americans, in terms of their preference for Coke over Pepsi. Calculate his p-value. (Hint: consider whether this is a one-tailed or two-tailed test.)
A. |
1.7498 |
|
B. |
0.1252 |
|
C. |
0.8749 |
|
D. |
0.2502 |
8)
Her guess of 75% will be outside her interval.
13)
std error =Se | =√(p*(1-p)/n) = | 0.0349 | ||
sample proportion p̂ | x/n= | 0.8000 | ||
test stat = z = | (p̂-p)/Se= | 1.15 |
option c:1.15
14)
critical value that would mark off his rejection region =1.645
15)
p-value. =0.2502
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