The police department of a major city needs to update its budget. For this purpose, they need to understand the variation in their fines collected from motorists for speeding. As a sample, they recorded the speeds of cars driving past a location with a 25 mph speed limit, a place that in the past has been known for producing fines. The mean of 100 representative readings was 28.77 mph, with a standard deviation of 3.54 mph. a) How many standard deviations from the mean would a car going the speed limit be? b) Which would be more unusual, a car traveling 38 mph or one going 15 mph?
μ = mean = 28.77
σ = standard deviation = 3,54
We find the z score for 25 mph to for how many standard deviations from the mean would a car going the speed limit be
z = -1.064971751
Negative sign to Z score means below the mean
Answer :-
A car going the speed limit be 1.064971751 standard deviation below the mean Speed
# b part
First we find the z score for 38
z = 2.607344633
Now we find Z score 15
z = -3.889830508
Here The going speed 15 mph is more unusual with a z score of -3.889830508 below the mean than the 38 mph with 2.607344633 above the mean
( beacuse Z score - 3.889830508 too far from the standard normal distribution mean ( 0 ) )
I hope this will help you :)
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