You’re the manager of the canning line at Avery Brewing Company. When the machines are operating properly, at least 12 ounces of beer is added to each can. A sample of 40 beers from the line yields a mean of 12.05 ounces with a standard deviation of 0.2 ounces. Do you think the canning line is operating properly?
Here, we have to use one sample t test for the population mean.
The null and alternative hypotheses are given as below:
H0: µ ≥ 12 versus Ha: µ < 12
This is a lower tailed test.
The test statistic formula is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
From given data, we have
µ = 12
Xbar = 12.05
S = 0.2
n = 40
df = n – 1 = 39
α = 0.05
Critical value = -1.6849
(by using t-table or excel)
t = (12.05 – 12)/[0.2/sqrt(40)]
t = 1.5811
P-value = 0.9390
(by using t-table)
P-value > α = 0.05
So, we do not reject the null hypothesis
There is sufficient evidence to conclude that the machines are operating properly.
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