A recent article in Bloomberg Businessweek listed the “Best Small Companies.” We are interested in the current results of the companies’ sales and earnings. A random sample of 12 companies was selected and the sales and earnings, in millions of dollars, are reported below. |
Company | Sales ($ millions) |
Earnings ($ millions) |
Company | Sales ($ millions) |
Earnings ($ millions) |
||||||||||||
Papa John's International | $ | 87.4 | $ | 4.9 | Checkmate Electronics | $ | 17.5 | $ | 2.6 | ||||||||
Applied Innovation | 18.6 | 4.4 | Royal Grip | 9.8 | 1.7 | ||||||||||||
Integracare | 17.4 | 1.3 | M-Wave | 19.6 | 3.5 | ||||||||||||
Wall Data | 71.7 | 8.0 | Serving-N-Slide | 53.7 | 8.2 | ||||||||||||
Davidson & Associates | 58.6 | 6.6 | Daig | 28.6 | 6.0 | ||||||||||||
Chico's FAS | 47.3 | 4.1 | Cobra Golf | 69.2 | 12.8 | ||||||||||||
Let sales be the independent variable and earnings be the dependent variable. (Round your answers to 3 decimal places.) |
a. | The coefficient of correlation is . |
b. | The coefficient of determination is . |
c. | The regression equation, with the coefficients, is Y' = + X |
d. |
For a small company with $44 million in sales, an estimate of the earnings is ($ millions). |
a. |
The coefficient of correlation is 0.690 |
b. | The coefficient of determination is 0.4761. Here we assumed to be a linear relationship between X and Y. However the cubic regression model seems more effective with coefficient of determination = 0.665 |
c. |
The regression equation, with the coefficients, is Y = 1.791 + 0.085X. However, it is simple regression model. If we use the cubic regression model the regression equation becomes Y=3.248-0.151X^3+0.008X^2-0.001X^3 |
d. |
For a small company with $44 million in sales, an estimate of the earnings is 5.545 ($ millions). Here we assume a simple linear regression model. For cubic regression model, for a small company with $44 million in sales, an estimate of the earnings is 6.456 ($ millions). |
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