The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested. However, the manufacturer thinks it would be better to use a diamond indenter so that all types of metal can be tested. Because of differences between the two types of indenters, it is suspected that the two methods will produce different hardness readings. The metal specimens to be tested are large enough so that two indentions can be made. Therefore, the manufacturer uses both indenters on each specimen and compares the hardness readings. Construct a 95% confidence interval to judge whether the two indenters result in different measurements. Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. LOADING... Click the icon to view the data table.
Specimen |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
|
---|---|---|---|---|---|---|---|---|---|---|
Steel ball |
5050 |
5757 |
6161 |
7070 |
6868 |
5454 |
6565 |
5151 |
5353 |
|
Diamond |
5252 |
5656 |
6161 |
7474 |
6969 |
5555 |
6868 |
5151 |
56 |
Confidence interval for difference between two population means of paired samples is given as below:
Confidence interval = Dbar ± t*SD/sqrt(n)
We take difference as diamond minus steel.
From given data, we have
Dbar = 1.444444444
Sd = 1.666666667
n = 9
df = n – 1 = 8
Confidence level = 95%
Critical t value = 2.3060
(by using t-table)
Confidence interval = Dbar ± t*SD/sqrt(n)
Confidence interval = 1.444444444 ± 2.3060*1.666666667/sqrt(9)
Confidence interval = 1.444444444 ± 1.2811
Lower limit = 1.444444444 - 1.2811 = 0.1633
Upper limit = 1.444444444 + 1.2811 = 2.7256
0.1633 < µd < 2.7256
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