An urn contains 2 black, 3 red, and 5 green balls. The balls are taken out one after the other 6 times and we are told that one of them is green. What is the probability that none of the other balls are green? Assume that the balls are non-identical in weight even though they have the same color
2 Black
3Red
5 Green balls
Total 10 Balls
From which we need to take 6 balls
Given 1 of the 6 balls is green
Now we need to find the probability that none of the other balls are green
i.e. remainig 5 balls are to be selected from 2 Black and 3 Red balls that is all of them to be seleted
Total permutations of selecting 5 balls from 10 remaining balls= 10C5 = 252
Total occurrences where we can have no green balls selected = 2C2 * 3C3 = 1
Hence the asked Probability = occurrences/total permutations
=1/252 =0.003968254
Hope the above answer has helped you in understanding the problem. Please upvote the ans if it has really helped you. Good Luck!!
Get Answers For Free
Most questions answered within 1 hours.