Assume the resting heart rates for a sample of individuals are normally distributed with a mean of 70 and a standard deviation of 20. Use the 68-95-99.7 rule to find the following quantities.
a. The relative frequency of rates less than 110 using the 68-95-99.7 rule is (Round to three decimal places as needed.)
b. The relative frequency of rates greater than 90 using the 68-95-99.7 rule is nothing. (Round to three decimal places as needed.)
c. The relative frequency of rates between 30 and 70 using the 68-95-99.7 rule is nothing. (Round to three decimal places as needed.)
Given that
mean = 70
standard deviation = 20
(A) we have to find probability that the rates less than 110
we can write 110 as 70+2*20 or mean+ 2*sd
so, 110 is 2 standard deviation above the mean
using the 68-95-99.7 rule, 97.7% of data is below 2 standard deviation above the mean
so, answer is 0.977
(B)
we have to find probability that the rates more than 90
we can write 90 as 70+1*20 or mean+ 1*sd
so, 90 is 1 standard deviation above the mean
using the 68-95-99.7 rule, 15.9% of data is above 1 standard deviation of the mean
so, answer is 0.159
(C) We can write 30 as 70-2*20 or mean - 2*sd
so, 30 is 2 standard deviation below the mean and 70 is the mean
using the 68-95-99.7 rule, 47.7% of data is between 2 standard deviation below the mean and the mean itself
so, answer is 0.477
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