Specify the distribution, including the name and value(s) of parameter(s), of X in Exercise 1.
A batch of 15 electric motors actually contains three defective motors. An inspector chooses 3 (without replacement). Find the mean and variance of X, the number of defective motors in the sample.
Solution:
It is given that , 3 out of 15 are defective.
Let p be the probability of success of event "motor is defective"
p = 3/15 = 0.2
An inspector chooses 3 (without replacement).
So , n = 3 , where n denotes number of trials.
Let X be the number of defective motors in the sample.
X follows Binomial(n = 3 , p = 0.2)
For binomial distribution ,
Mean = n * p = 3 * 0.2 = 0.6
Mean of X is 0.6
Variance = n * p * (1 - p) = 3 * 0.2 * (1 - 0.2) = 0.48
Variance of X is 0.48
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