a. Given log(P(S|x)/(1-P(S|x))= -43.37 + 0.4897x, where
P(S|x)=probability of success for test score x. Then
P(S|x)=exp(-43.37 + 0.4897x)/(1+exp(-43.37 + 0.4897x))
Then P(S|x=93)=exp(-43.37 + 0.4897*93)/(1+exp(-43.37 + 0.4897*93))= 0.897716
b. Odds ratio=P(S|x=93)/(1-P(S|x=93))=exp(-43.37 + 0.4897*93)=8.776696
Thus for a one-unit increase in the score, the expected change in log odds is 0.4897.
Since exp(.4897)=1.6318, we can say for a one-unit increase in test score, about 63% increase in the odds of success is expected .
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