1. In the following table of paired data the variable x represents the opening
bid suggested by an auctioneer and y represents the final winning bid for
several items.
x 1500 500 450 400 300
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y 750 550 125 275 125
Find the equation of the regression line for the data in Problem 1. Round your slope and y-intercept to three decimal places.
2. Use your regression line equation to predict the final bid
on an item with suggest opening bid $425.
Round your answer to the nearest whole number.
Solution:
slope of the regression euqation can be calculated as
b = n*summation(X*Y) - Summation(X)*summartion(Y) /
n*summation(X^2) - (summation(X))^2
X |
Y |
X*Y |
X^2 |
Y^2 |
1500 |
750 |
1125000 |
2250000 |
562500 |
500 |
550 |
275000 |
250000 |
302500 |
450 |
125 |
56250 |
202500 |
15625 |
400 |
275 |
110000 |
160000 |
75625 |
300 |
125 |
37500 |
90000 |
15625 |
3150 |
1825 |
1603750 |
2952500 |
971875 |
b = 5*1603750 - (3150*1825) / (5*2952500 -3150*3150)
b = 2270000/4840000 = 0.4690
Intercept can be calculated as
a = summation(Y) - b*Summation(X) / n
a = (1825 -(0.4690*3150))/5 = (1825 - 1477.37) /5 = 69.52
So linear regression equation is
Y = a +bX
Y = 69.524 + 0.469 *X
Solution(2)
Given X = 425
SO Y = 69.524 + 0.469*425 = 69.524 + 199.325 = 268.849 or 269
So final bid on an item with sugget opening bid $425 is 269
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