Use 3 decimal place accuracy a. compute the correlation coefficient b. slope of the regression equation c. y-intercept |
The statistical software output for this problem is :
Simple linear regression results:
Dependent Variable: y
Independent Variable: x
y = -2.89375 + 2.3066406 x
Sample size: 5
R (correlation coefficient) = 0.93772223
R-sq = 0.87932298
Estimate of error standard deviation: 0.70602873
Parameter estimates:
Parameter | Estimate | Std. Err. | Alternative | DF | T-Stat | P-value |
---|---|---|---|---|---|---|
Intercept | -2.89375 | 2.2326589 | ≠ 0 | 3 | -1.2961004 | 0.2856 |
Slope | 2.3066406 | 0.49335257 | ≠ 0 | 3 | 4.6754406 | 0.0185 |
a) The correlation coefficient = 0.937
b) slope of the regression equation = 2.306
c) y-intercept = -2.893
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