Based on a smartphone survey, assume that 41% of adults with smartphones use them in theaters. In a separate survey of 264 adults with smartphones, it is found that 105 use them in theaters. a. If the 41% rate is correct, find the probability of getting 105 or fewer smartphone owners who use them in theaters. b. Is the result of 105 significantly low?
Based on a smartphone survey, assume that 41% of adults with smartphones use them in theaters. In a separate survey of 264 adults with smartphones, it is found that 105 use them in theaters.
If the 41% rate is correct, find the probability of getting 105 or fewer smartphone owners who use them in theaters.
n=264, p=0.41
normal approximation to binomial used.
Expectation = np = 108.24
Variance = np(1 - p) = 63.8616
Standard deviation = 7.9913
With continuity correction , z value for 105, z =(105.5-108.24)/7.9913 = -0.34
P( x ≤105) = P(z < -0.34)
=0.3669
b. Is the result of 105 significantly low?
Since P( x ≤105) =0.3669 which is > 0.05, the result of 105 is not significantly low.
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