Question

Find the following z values for the standard normal variable Z. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)

a. P(Z ≤ z) = 0.8133

b. P(Z > z) = 0.8125

c. P(−z ≤ Z ≤ z) = 0.96

d. P(0 ≤ Z ≤ z) = 0.2991

Answer #1

Solution

Using standard normal table,

(a)

P(Z z) = 0.8133

P(Z 0.89) = 0.8133

z value = 0.89

(b)

P(Z > z) = 0.8125

1 - P(Z < z) = 0.8125

P(Z < z) = 1 - 0.8125 = 0.1875

P(Z < -0.89) = 0.1875

z value = -0.89

(c)

P(-z Z z) = 0.96

P(Z z) - P(Z -z) = 0.96

2P(Z z) - 1 = 0.96

P(Z z) = 1 + 0.96 = 1.96

P(Z z) = 1.96 / 2 = 0.98

P(Z 2.05) = 0.98

z value = 2.05

(d) .

P(0 Z z) = 0.2991

P(Z z) - P(Z 0) = 0.2991

P(Z z) = P(Z 0) + 0.2991

P(Z z) = 0.5 + 0.2991 = 0.7991

P(Z 0.84) =0.7991

z value = 0.84

Find the following z values for the standard normal
variable Z. (Negative values should be indicated
by a minus sign. Round your answers to 2 decimal
places.)
a.
P(Z ≤
z) = 0.9477
b.
P(Z >
z) = 0.6300
c.
P(−z ≤
Z ≤ z) = 0.85
d.
P(0 ≤ Z ≤
z) = 0.2034

Find the following z values for the standard normal
variable Z. Use Table 1. (Negative values should
be indicated by a minus sign. Round your answers to 2 decimal
places.)
a.
P(Z ≤
z) = 0.9478
b.
P(Z >
z) = 0.6140
c.
P(−z ≤
Z ≤ z) = 0.80
d.
P(0 ≤ Z ≤
z) = 0.2392
Hints

Find the following z values for the standard normal
variable Z. (Use Excel command instead of
the z table.Negative values
should be indicated by a minus sign. Round your answers to 2
decimal places.)
a.
P(Z ≤ z) = 0.8485
b.
P(Z > z) = 0.7329
c.
P(−z ≤ Z ≤ z) = 0.96
d.
P(0 ≤ Z ≤ z) = 0.2517

Find the following z values for the standard normal variable Z.
(Use Excel command instead of the z table. Negative values should
be indicated by a minus sign. Round your answers to 2 decimal
places.)
a.
P(Z ≤ z) = 0.9477
b.
P(Z > z) = 0.63
c.
P(−z ≤ Z ≤ z) = 0.85
d.
P(0 ≤ Z ≤ z) = 0.2034

Find the following z values for the standard normal variable Z.
(You may find it useful to reference the z table. Negative values
should be indicated by a minus sign. Round your answers to 3
decimal places.)
a. P(Z ≤ z) = 0.1065
b. P(z ≤ Z ≤ 0) = 0.1746
c. P(Z > z ) = 0.9412
d. P(0.4 ≤ Z ≤ z) = 0.3177

Find the following z values for the standard normal variable Z.
(You may find it useful to reference the z table. Negative values
should be indicated by a minus sign. Round your answers to 2
decimal places.)
a. P(Z ≤ z) = 0.9478
b. P(Z > z) = 0.6321
c. P(-z ≤ Z ≤ z ) = 0.88
d. P( 0 ≤ Z ≤ z) = 0.3232
Please show work, thank you.

Find the following z values for the standard normal
variable Z. (You may find it
useful to reference the
z table.Negative values should be
indicated by a minus sign. Round your answers to 3 decimal
places.)
a.
P(Z ≤ z)
= 0.1022
b.
P(z ≤ Z ≤
0) = 0.1641
c.
P(Z > z ) = 0.9719
d.
P(0.29 ≤ Z ≤ z) = 0.3777

A: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≤ 1.11) =
B: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≥ −1.24) =
C: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(−1.78 ≤ z...

let
z be a random variable with a standard normal distrubtion. find the
indicated probability (round your answer to four decimal places).
a) P(z ≥ -1.53)=
b) P(z ≤ -2.04)=
c) P(-2.00 ≤ z ≤ 1.05)=
d) P(0 ≤ z ≤ 0.50)=

Let z be a random variable with a standard normal distribution.
Find the indicated probability. (Round your answer to four decimal
places.) P(z ? ?0.25)
Let z be a random variable with a standard normal distribution.
Find the indicated probability. (Round your answer to four decimal
places.) P(z ? 1.24)
Let z be a random variable with a standard normal distribution.
Find the indicated probability. (Enter your answer to four decimal
places.) P(?2.20 ? z ? 1.08)

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