A recent poll of 809 randomly selected registered voters revealed that 426 plan to vote for your candidate in the coming election.
Is the observed percentage more than 50%?
Is the observed percentage significantly more than 50%? How do you know? Base your answer on a two-sided test.
A recent poll of 809 randomly selected registered voters revealed that 426 plan to vote for your candidate in the coming election.
Is the observed percentage more than 50%?
We are given
n = 809
x = 426
Observed proportion = x/n = 426/809 = 0.526576
Observed percentage = 52.66%
Yes, observed percentage is more than 50%.
Is the observed percentage significantly more than 50%? How do you know? Base your answer on a two-sided test.
Here, we have to use z test for population proportion.
H0: p = 0.5 versus Ha: p ≠ 0.5
This is a two sided test.
Test statistic formula for this test is given as below:
Z = (p̂ - p)/sqrt(pq/n)
Where, p̂ = Sample proportion, p is population proportion, q = 1 - p, and n is sample size
x = number of items of interest = 426
n = sample size = 809
p̂ = x/n = 0.526576
p = 0.5
q = 1 - p = 0.5
Z = (p̂ - p)/sqrt(pq/n)
Z = (0.526576 – 0.5)/sqrt(0.5*0.5/809)
Z = 1.5118
P-value = 0.1306
(by using z-table)
P-value > α = 0.05
So, we do not reject the null hypothesis
There is insufficient evidence to conclude that the population percentage is significantly more than 50%.
The observed percentage is not more than 50%.
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