Suppose the average commute time of your employees is unknown. The standard deviation of their commute time is estimated as 27.6 minutes.
How many employees must be included in a sample to create a 99 percent confidence interval for the average commute time with a confidence interval width of no more than 17 minutes?
Note that the correct answer will be evaluated based on the z-values in the summary table in the Teaching Materials section.
Remember to round your answer up to an integer.
Solution :
Given that,
standard deviation = = 27.6
width = 17
margin of error = E = width / 2 = 17 / 2 = 8.5
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z 0.005 = 2.576
Sample size = n = ((Z/2 * ) / E)2
= ((2.575 * 27.6) / 8.5)2
= 69.9 = 70
Sample size = n = 70 employees .
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