For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
Case studies showed that out of 10,035 convicts who escaped from
certain prisons, only 7676 were recaptured.
(a) Let p represent the proportion of all escaped
convicts who will eventually be recaptured. Find a point estimate
for p. (Round your answer to four decimal places.)
(b) Find a 99% confidence interval for p. (Round your
answers to three decimal places.)
lower limit | |
upper limit |
a)
Number of Items of Interest, x =
7676
Sample Size, n = 10035
point estimate for p=p̂ = x/n = 0.7649
b)
Level of Significance, α = 0.01
Sample Proportion , p̂ = 0.7649
z -value = "Zα/2 = 2.5758 [excel function
=normsinv(0.01/2)
Standard Error , SE = √[p̂(1-p̂)/n] =
0.0042
margin of error , E = Z*SE = 0.0109
Confidence Interval
Interval Lower Limit , = p̂ - E =
0.754
Interval Upper Limit , = p̂ + E =
0.776
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